Find the current drawn from the battery by network of four resistors shown in the figure .....
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Answer:
R1=10+10 =20ohm
R2=10+10 = 20 ohm
1/R=1/R1 + 1/R2
1/R = 1/10 +1/10
1/R= 2/20
1/R=1/10
R = 10 ohm
V=3V
V=IR
I=V/R
I=3/10
I=0.3 A
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