Question

Find the current draws from the 6V battery.​

Answer 1

Answer:

Given,

Potential Difference = 6 V

Total Resistance = 2+6+3+1.5

= 12.5

V = IR

=> I = V

R

=> I = 6

12.5

=> I = 0.48 Amperes

HERE'S THE ANSWER... HOPE IT HELPS YOU!

.

.

.

.

.

.

.

THANK YOU!!

Answer 2

Answer:

Current drawn from 6 V battery is 4 Ampere .

Explanation:

• In the given circuit, 6 ohm and 2 ohm resistor are in parallel combination. There effective resistance ( say R(p) ) is given by:

$\frac{1}{R(p)} = \frac{1}{2} + \frac{1}{6} \\ \frac{1}{R(p)} = \frac{3 + 1}{6} \\ \frac{1}{R(p)} = \frac{4}{6} \\ R(p) = \frac{6}{4} = \frac{3}{2} = 1.5 \: ohms$

• Now, 1.5 ohms and R(p) are in series combination. Thus, there equivalent resistance (say R(s)) is given by :

$R(s) = 1.5 + 1.5 \\ R(s) = 3 \: ohms$

• Now, R(s) resistance is in parallel with 3 ohm resistance. Net equivalent resistance R(eq) of total circuit is

$\frac{1}{R(eq)} = \frac{1}{3} + \frac{1}{3} = \frac{2}{3} \\ R(eq) = \frac{3}{2} = 1.5 \: ohms$

• The voltage in the circuit is 6 V and equivalent resistance is 1.5 ohms.
• Current, I in the circuit is given by Ohm's law:

$Current, I = \frac{V}{R} \\ I = \frac{6}{1.5} = 4 \: A$

• Hence, current in the circuit is 4 A.