Question

Find the current flowing through the following electric circuit.

Answer 1

AnsWer :

0.5 A.

SolutioN :

• Series Combination : When follow only one path, and direction of current be same, it said to be Series Combination.
• Rs = R1 + R2 + R3 + ... + Rn.

• Parellel Combination : When current follow different path and direction change,it said to be Parellel Combination.
• 1 / Rp = 1 / R1 + 1 / R2 + 1 / R3 + ... + 1 / Rn.

We have,

• 3.6Ω.
• R2 = 6Ω.
• R3 = 1Ω.
• R4 = 3Ω.
• R5 = 3Ω.

✎ We are notice,

• R3 and R4 are connected in Series Combination.

☛ Case 1.

$\tt : \implies R_S= R_3 + R_4.$

$\tt : \implies R_S= 1+ 3.$

$\tt : \implies R_S= 4\Omega.$

$\rule{90}1$

☛ Case 2.

$\tt : \implies \dfrac{1}{R_P} = \dfrac{1}{R_3} + \dfrac{1}{R_4}$

$\tt : \implies \dfrac{1}{R_P} = \dfrac{1}{3} + \dfrac{1}{6}$

$\tt : \implies \dfrac{1}{R_P} = \dfrac{2 + 1}{6}$

$\tt : \implies \dfrac{1}{R_P} = \dfrac{3}{6}$

$\tt : \implies R_P= 2 \Omega .$

$\rule{90}1$

✎ Now, All reaming connect in Series Combination.

$\tt : \implies R_s = 3 . 6 + 2 + 3$

$\tt : \implies R_s = 8.6\Omega.$

$\rule{90}1$

✎ Now, Let's Find Current flow in Circuits.

We know,

• V = IR.
• V ( Voltage )
• I ( Current )
• R ( Resistance )

$\tt : \implies V = I\times R$

$\tt : \implies 4.5 = I\times 8.6$

$\tt : \implies \dfrac{4.5}{8.6} = I$

$\tt : \implies I = 0.5 A.$

✡ Therefore,0.5 A of current flow in the given circuit.