Find the current (I) in the circuit shown :-
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Answer:
0.1A
Explanation:
the circuit has two Resistors (30 & 30 ohm) in series and these are in parallel with other resistor (30ohm)
hence R' = R1+R2
R' = 30 + 30 =60 ohm (series)
R" = R'×R3/(R'+R3) (parallel)
R" = 60 ×30/(60+30) = 20 ohm
But I = V/R" (ohm's law)
hence current I = 2/20= 0.1A
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