Question

Find the current I shown in Figure 3 ​

Answer 1

Explanation:

potential drop across both the terminal is same.

I¹ x 10 = I x 17

I¹/I = 1.7 A

I¹ + I = 10 /17

I ( I¹/I + 1) = 10/17

I ( 1.7 + 1) = 10/17

I x 2.7 = 10/17

I = 100 / (17 x 27) A

Answer 2

Correct Question :-

Find the voltage from the Given Figure 3 .

Given :-

The net current in the circuit i.e 10/17 A and two resistors are connected in parallel with resistances 10 ohm and 17 ohm respectively .

To Find :-

The Net voltage through the circuit .

Used Concepts :-

• Ohm's Law .

Solution :-

Let , The given Resistors be R1 , R2 . Then ,

R1 = 17 ohm

R2 = 10 ohm

The net current through circuit = 10/17 A = I

Again Let , The net resistance of the Circuit = Rp .

Then , The given resistances are in parallel . So ,

1/Rp = 1/R1 + 1/R2

=> 1/Rp = 1/17 + 1/10

=> 1/Rp = 17 + 10 / 170

=> 1/Rp = 27/170

Therefore , Rp = 170/27 ohm .

Now , Let the net voltage through the circuit = "V"

So , By ohm's law ,

V = IRp

=> V = 10/17 × 170/27

=> V = 100/27 volts

Henceforth , The Required Answer is 100/27 volts .