find the current through 10 ohm resistor for the following circuit
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Answer:
hence the current through 10ohm resistor is 3.2A
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Concept:
Resistance is measured as the opposition to current flow in an electrical circuit. It is expressed as R = V/I
Given:
Resistance of resistor = 10 ohm
R1 = 2 ohm
R2 = 10 ohm
R3 = 6 ohm
R4 = 3 ohm
Find:
We need to determine the current flowing through the circuit.
Solution:
R3 and R4 are connected in series therefore- 6 +3 = 9 = R5
Resistance in parallel = 1/R1 + 1/R2 + 1/R5
Resistance in parallel = 1/2 + 1/10 + 1/9
Resistance in parallel = 45+9+10/90
R = 64/90 ohm
R = 0.711 ohms
Therefore, voltage, V = IR
V = 4(0.711)
V = 2.84 V
Current through the 10 ohm resistor is-
V = IR
I = V/R
I = 2.84 / 0.711
I = 3.99 A ≈ 4A
Thus, the current through the 10-ohm resistor for the given circuit is 4A.
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