find the current through 4ohms using Norton's theorem
Answers
Answered by
105
Explanation:
RTH = + 14 − 6 = 8 V RTH = 2 ohms looking into the circuit form X-Y terminals after de-activating the sources IL = 8/2 + 4 = 4/3 Amp. Method 3 : Norton's Theorem : Redraw modifying as in Fig.IN = 2 + 2 = 4 Amp. This is because X and Y are at ground potential 2-ohm resistor has to carry 3 A and hence from 5-Amp.
Answered by
70
Answer:
RTH = + 14 − 6 = 8 V RTH = 2 ohms looking into the circuit form X-Y terminals after de-activating the sources IL = 8/2 + 4 = 4/3 Amp. Method 3 : Norton's Theorem : Redraw modifying as in Fig.IN = 2 + 2 = 4 Amp. This is because X and Y are at ground potential 2-ohm resistor has to carry 3 A and hence from 5-Amp.
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