Question

find the current through 8 ohm resistor​

Answer 1

Answer:

Resistors let you choose how much current flows for a given voltage since you can think of wires as having no resistance (simplified). In short: Resistors limit the flow of electrons, reducing current. Voltage comes about by the potential energy difference across the resistor.

Explanation:

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Answer 2

Current flowing through 8 ohm resistor is 1 Ampere.

Explanation:

Let potential at the across the node is v. ( the point which is connecting all resistance).

Now, In bottom 4 ohm reistance one point is at ground i.e potential there is 0 V.

Therefore, current flowing across the 4 ohm resistance is, $i_1=\dfrac{v-0}{4}=\dfrac{v}{4}$

( Here we assume v to be at higher potential).

Similarly at other 4 ohm resistor, $i_2=\dfrac{40-v}{4}$.

Also , in 8 ohm resistor, $i_3=\dfrac{10-v}{8}.$

Now , we know in a node total current coming is equivalent to total current leaving.

Therefore,

$i_1=i_2+i_3\\\dfrac{v}{4}=\dfrac{40-v}{4}+\dfrac{10-v}{8}$

Solving above equation we get,

v=18 Volts.

Therefore, current flowing through * ohm resistance is $i_3=\dfrac{10-v}{8}.=\dfrac{10-18}{8}=-1\ Ampere$

( here direction is upwards because we considered current is flowing upside down therefore, it is negative).

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