Chemistry, asked by DurgaGanesh2775, 11 months ago

Find the currents through the three resistors shown in the figure (32-E9).
Figure32-E9

Answers

Answered by shilpa85475
0

The current via the 6 Ω and 4 Ω resistors is 0.2 A .

Explanation:

  • We can observe from the figure that there will be a flow of current only in the first loop (loop 1).
  • This is because of the flow of current in the slightest resistive path.
  • The current will pass via the current that is linked to the wire that is in parallel in loop 2 to the 4 Ω resistor.

Therefore, in loop 2, no current will be there via the 4 Ω resistor.

Applying KVL for loop 1, we obtain:

4i + 6i + - 4 + 2 = 0

⇒10i = 2

⇒i = 0.2 A

∴ The current via the 6 Ω and 4 Ω resistors, i = 0.2 A

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