Question

find the curve surface area of a right circular cone whose rdious is 5 cm and vertical height is 15cm

Answer 1

radius=5cm
height =15cm
therefore slant height =
$\sqrt{ {5}^{2} + {15}^{2} } = \sqrt{25 + 225} = \sqrt{250} = 5 \sqrt{10} cm$
therefore curved surface area=
$\pi \times 5 \times 5 \sqrt{10} = 25 \sqrt{10} \times \frac{22}{7} = \frac{550}{7} \times \sqrt{10} sq. cm$

Answer 2

Step-by-step explanation:

${5}^{2} + 15 {}^{2} = 250$

$250 = {l}^{2}$

$l = \sqrt{250 =} 15.81$