Question

find the curved surface area and total surface area of each cylinder whose dimension are radius of base 5.6meter and height 1.25m​

Answer 1

Answer:

308m^2 and 294. 27m^2

Step-by-step explanation:

CSA=2×22/7×5.6×1.25

=44×0.8×1.25

=308m^2

TSA=2×22/7×5.6 (5.6+1.25)

=34.2×6.85

=294.27m^2

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{C.S.A\:of\:cylinder=44\:m}^{2}}}$

$\green{\therefore{\text{T.S.A\:of\:cylinder=241.12\:m}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Radius(r) = 5.6\: m} \\ \\ : \implies \text{Height(h) = 1.25\: m} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{C.S.A \: of \: cylinder = ? }\\ \\ : \implies \text{T.S.A\: of \: cylinder = ? }$

• According to given question :

$\bold{As \: we \: know \: that } \\ : \implies \text{C.S.A\: of \: cylinder} =2\pi rh \\ \\ : \implies \text{C.S.A\: of \: cylinder} =2 \times \frac{ 22}{7} \times 5.6 \times 1.25 \\ \\ : \implies \text{C.S.A\: of \: cylinder} =2 \times 22 \times 1 \\ \\ \green{ : \implies \text{C.S.A\: of \: cylinder} =44 \: {m}^{2}} \\ \\ \bold{As \: we \: know \: that} \\ : \implies \text{T.S.A\: of \: cylinder} =2\pi r(h + r) \\ \\ : \implies \text{T.S.A\: of \: cylinder} =2 \times \frac{22}{7} \times 5.6(1.25+ 5.6) \\ \\ : \implies \text{T.S.A\: of \: cylinder} =2 \times 22 \times 5.48 \\ \\ \green{ : \implies \text{T.S.A\: of \: cylinder} =241.12\: {m}^{2} }$