Question

find the curved surface area of a garden roller whose length is 1.5m and radius is 70cm. how much area can it level in 200 revolution

Answer 1

Answer:

Step-by-step explanation:

Curved surface area( csa ) of cylinder= 2πrh

= 2*22*70*1.5/70 (make sure it's all the multiplication divided by 70)

= 4620/70

= 66

Plz do inform if ans is right!

Answer 2

c.s.a of roler=2*pi*r*h =2*22/7*0.7*1.5=6.6m^2   1 revolution level area=6.6m^2     200 revolution level area=6.6*200=1320m^2