find the curved surface area of a garden roller whose length is 1.5m and radius is 70cm. how much area can it level in 200 revolution
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Answer:
Step-by-step explanation:
Curved surface area( csa ) of cylinder= 2πrh
= 2*22*70*1.5/70 (make sure it's all the multiplication divided by 70)
= 4620/70
= 66
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vk314755:
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c.s.a of roler=2*pi*r*h =2*22/7*0.7*1.5=6.6m^2 1 revolution level area=6.6m^2 200 revolution level area=6.6*200=1320m^2
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