Question

Find the curved surface area of a right circular cylinder circumference of whose base is 88cm and height is 5​

Answer 1

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C.S.A of cylinder= 440 cm^2

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Step-by-step explanation:

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Circumference of base of Cylinder = 88 cm

==> 2πR = 88

==> 2 × 22/7 × R = 88

==> 44/7 × R= 88

==> R = 88 × 7/44

(Cut 88 by 44 we have)

==> R = 14 (Radius)

Hight of cylinder (H) = 5 cm

C.S.A of cylinder = 2πRH

$c.s.a \: of \: cylinder = 2 \times \frac{22}{7} \times 14 \times 5 \\ \\ = \frac{3080}{7} \: {cm}^{2} \\ \\ = \: 440 \: {cm}^{2}$

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Answer 2

Answer:

Given,

base of the cylinder is = 88cm (diameter)

then, radius = d/2 = 88/2

= 44cm

height of the cylinder is = 5 cm

We Know That,

CSA of a right circular cylinder is = 2πrh

=> 2×22/7× 44×5

( after calucalation we get)

=>1,382.85

HENCE PROVED