find the curved surface area of cube whose Total surface area is given (a) 486 (b) 150
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Answered by
17
Case 1 :
→ T.S.A of cube = 486
→ 6a² = 486
→ a² = 486 / 6
→ a² = 81
→ a = √81
→ a = 9
Now
C.S.A of the cube = 4a²
→ 4 × 9²
→ 4 × 81
→ 324 unit²
Case 2 :-
→ T.S.A of cube = 150
→ 6a² = 150
→ a² = 150 / 6
→ a² = 25
→ a = √25
→ a = 5
Now
C.S.A of the cube = 4a²
→ 4 × 5²
→ 4 × 25
→ 100 unit²
Curved surface area of the cubes are 324 unit² amd 100 unit²
Answered by
7
CSA of cube=4a².
TSA of cube=6a²
(1).486/6=a²
✓81=9=a.
LSA=4(9)²=4(81)=324.
(2). 150/6=a²
✓25=5=a
LSA=4(5)²=4(25)=100.
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