Question

find the curved surface area of cuboidal pit 8 metre long 6 metre broad and 3m deep​

Answer 1

Answer:

csa = 180cm^2

Step-by-step explanation:

given :

length = 8m

breadth = 6m

and height = 3m

CSA = 2(lb+bh+hl)

= 2(8*6+6*3+3*8)

= 2(48+18+24)

= 2(90)

= 180cm^2

Answer 2

Correct Question :

Find the curved surface area of cuboidal pit 8 m long , 6 m and 3 m depth .

Given :

• Length of cuboidal pit= 8 m.
• Breadth of cuboidal pit= 6 m.
• Height of cuboidal pit = 3 m.

To find :

• Curved surface area of cuboidal pit.

Solution :

• Length = 8 m.
• Breadth = 6 m.
• Height = 3 m.

We know,

${\boxed{\green{\bold{CSA\:of\: cuboid=2(l+b)h}}}}$

$\sf{CSA\:of\: cuboid=2(l+b)h}$

$\implies\sf{CSA\:of\: cuboid=2(8+6)\times\:3\:m^2}$

$\implies\sf{CSA\:of\: cuboid=2\times\:14\times\:3\:m^2}$

$\implies\sf{CSA\: of\: cuboid=84\:m^2}$

Therefore , the curved surface area of cuboidal pit is 84 m².

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More information :-

★ Some formulas :

•TSA of cuboid=2(lb+lh+bh)

•Volume of cuboid=l×b×h

•Diagonal of cuboid =√(l²+b²+h²)

•TSA of cube = 6a²

• Volume of cube=a³

• Diagonal of cube = a√3

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