Question

Find the de-broglie wavelength of a bullet of mass 0.02 kg moving with velocity 300m/sec.

Answer 1

lambda=h/mv
=6.6*10-34/0.02*300
=6.6*10-34/6
=1.1*10-34

Answer 2

Given that,

Mass of bullet, m = 0.02 kg

Velocity, v = 300 m/s

To find,

De-Broglie wavelength

Solution,

The De-Broglie wavelength of an object is given by :

$\lambda=\dfrac{h}{mv}$

h is Plank's constant

$\lambda=\dfrac{6.63\times 10^{-34}}{0.02\times 300}\\\\\lambda=1.105\times 10^{-34}\ m$

So, the De-Broglie wavelength of the bullet is $1.105\times 10^{-34}\ m$.

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De-Broglie wavelength

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