Find the density of a 3.6 m sulphuric acid solution that is 29% h2 s o4 by mass
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Molarity (M) of = 3.6M. Percent by mass of present in solution (w/W) =29% i.e 29 gram of is present per 100 grams of solution having density d (lets assume that) Also Molecular mass of is 98. Now as Volume is 1 litre so 3.6 moles of is present in 1 litre solution. So mass of present is 3.6 × 98 = 352.8 grams.
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