Math, asked by BrainlyHelper, 1 year ago

Find the depth of a cylindrical tank of radius 10.5 cm, if its capacity is equal to that of a rectangular tank of size 15 cm × 11 cm × 10.5 cm.

Answers

Answered by nikitasingh79
52
SOLUTION:
Given: Radius of a cylindrical tank = 10.5 cm
Length of a tank (l) = 15 cm
Breadth of a tank (b) = 11 cm
Height of a tank (h) = 10.5 cm

Let H be the depth of a cylindrical tank.

Capacity(volume) of cylindrical tank =  capacity(volume) of rectangular tank (given)
πr²H = l × b × h

22/7 × (10.5)² × H = 15 × 11 × 10.5

H = (15 × 11 × 10.5 × 7) / (22 × 10.5 × 10.5)
H = 15 / ( 2 × 1.5)
H = 15 / 3 cm = 5 cm

Hence, the depth of a cylindrical tank is 5 cm

HOPE THIS WILL HELP YOU..
Answered by Anonymous
12
hiii!!!

here's ur answer...

ATQ,

both the capacity of cylindrical tank and rectangular tank are equal.

therefore volume of cylindrical tank = volume of rectangular tank.

given the Length of the rectangular tank = 15cm

breadth of the rectangular tank = 11cm

height of the rectangular tank = 10.5cm

volume of the rectangular tank = l × b × h

= 15 × 11 × 10.5

= 1732.5cm³

therefore volume of the cylindrical tank is also 1732.5cm³

radius of the cylindrical tank is given 10.5cm.

volume of the cylindrical tank = 1732.5cm³

therefore πr²h = 1732.5cm³

==> 22/7 × 10.5 × 10.5 × h = 1732.5cm³

==> 2425.5/7 × h = 1732.5cm³

==> 346.5 × h = 1732.5cm³

==> h = 1732.5/346.5

==> h = 5cm

depth of the cylindrical tank is 5cm.

hope this helps..!!
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