find the derivate of e^cot inverse x w.r to tan inverse x
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Let y=cot
−1
(x
3
)
Differentiating w.r.t. x, we get
dx
dy
=
dx
d
[cot
−1
(x
3
)]
=
1+(x
3
)
2
−1
⋅
dx
d
(x
3
)
=
1+x
6
−1
×3x
2
=
1+x
6
−3x
2
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