find the derivative
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d/dxcos root 3
=-sin root 3×d/dx root 3
=-sinroot3/2root3
=-sin root 3×d/dx root 3
=-sinroot3/2root3
swayanprakashpanda28:
what is your class
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Step-by-step explanation:
Let say :
y = cos ( √ 3 )
We have find y' :
We know :
( cos x )' = - sin x
Derivative of constant is zero!
Apply chain rule :
Diff. w.r.t. x :
y = cos ( √ 3 )
y' = - sin y ( √ 3 ) . ( √ 3 )'
y' = - sin ( √ 3 ) . 0
= > y' = 0
The derivative is zero because the differentiation variable ' x ' is independent variable!
Hence we get required answer!
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