Question

find the derivative of secx cos2x

Answer 1

ur answer ................

Answer 2

Here is ur answer buddy!!
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Formula to be used is d(U. V) = udv + vdu
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d(secx. Cos2x) /dx

= secx × d(cos2x)/dx + cos2x × d(secx)/dx

= secx × (- sin2x) ×2 + Cos2x × secx.tanx

= secx.tanx × cos2x - 2secx.sin2x

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Hope this is ur required answer.

Proud to help you.