Question

find the derivative of sin2x using first principle​

Answer 1

Step-by-step explanation:

I hope you're answers this

Answer 2

sin^2x can be expressed as (sin x)2^

Let f(x) = (sin x)2^

It can be written as f(u) = u^2 x where u = sin x.

f´(u) = 2u and u´= cos x

so that multiplying together we get

f´(x) = 2u·cos x = 2 sin x cos x

Answer

The derivative of sin2x = 2 sin x cos x