Question

find
the derivative of sinx/1-cosx​

Answer 1

Step-by-step explanation:

We know , sinx = 2 sin(x/2) cos(x/2). ; 1-cosx = 2{sin(x/2)}^2

now , sinx / 1-cosx

= 2 sin(x/2) cos(x/2) / 2 {sin(x/2)}^2

= d/dx cot(x/2)

= -cosec{ (x/2)}^2 × 1/2