Math, asked by sahilbhai9673, 11 months ago

find the derivative of sinX.cosX​

Answers

Answered by Anonymous
1

Step-by-step explanation:

The product rule can be used to differentiate any function of the form

f

(

x

)

=

g

(

x

)

h

(

x

)

. It states that

f

'

(

x

)

=

g

'

(

x

)

h

(

x

)

+

g

(

x

)

h

'

(

x

)

.

The derivative of

sin

x

is

cos

x

and the derivative of

cos

x

is

sin

x

.

f

'

(

x

)

=

cos

x

(

cos

x

)

+

sin

x

(

sin

x

)

f

'

(

x

)

=

cos

2

x

sin

2

x

Use the identity

cos

2

x

=

cos

2

x

sin

2

x

:

f

'

(

x

)

=

cos

2

x

Answered by Anonymous
3

Answer:

The product rule can be used to differentiate any function of the form

The product rule can be used to differentiate any function of the form f(x)=g(x)h(x). It states that f'(x)=g'(x)h(x)+g(x)h'(x).

The product rule can be used to differentiate any function of the form f(x)=g(x)h(x). It states that f'(x)=g'(x)h(x)+g(x)h'(x).The derivative of sinx is cox

The product rule can be used to differentiate any function of the form f(x)=g(x)h(x). It states that f'(x)=g'(x)h(x)+g(x)h'(x).The derivative of sinx is cox and the derivative of

The product rule can be used to differentiate any function of the form f(x)=g(x)h(x). It states that f'(x)=g'(x)h(x)+g(x)h'(x).The derivative of sinx is cox and the derivative of cosx is -sinx.f'(x)=cosx(cos+sinx(−sinx)f'(x)=cos2x−sin2x

+sinx(−sinx)f'(x)=cos2x−sin2xUse the identity

+sinx(−sinx)f'(x)=cos2x−sin2xUse the identity cos2x=cos2x−sin2x:f'(x)=cos2x

+sinx(−sinx)f'(x)=cos2x−sin2xUse the identity cos2x=cos2x−sin2x:f'(x)=cos2xHopefully this helps!

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