Question

find the derivative of
$3 {x}^{4} - 8 {x}^{3} + 12 {x}^{2} - 48x + 25$
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Answer 1

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

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Q:-find the derivative of

$3 {x}^{4} - 8 {x}^{3} + 12 {x}^{2} - 48x + 25$

$\bf\huge\underbrace{answer}$

------>>>>Here is your answer<<<<--------

$let \: f(x) = 3 {x}^{4} - 8 {x}^{3} + 12 {x}^{2} - 48x + 25$

$➠f'(x) = \frac{d(3 {x}^{4} - 8 {x}^{3} + 12 {x}^{2} - 48x + 25) }{dx}$

$➠f'(x) = 3 \times 4 {x}^{3} - 8 \times 3 {x}^{2} + 12 \times 2x - 48 + 0$

$➠f'(x) = 12 {x}^{3} - 24 {x}^{2} + 24x - 48$

$➠f'(x) = 12( {x}^{3} - 2 {x}^{2} + 2x - 4)$

HOPE IT HELPS YOU..

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Answer 2

Answer:

f¹(x) = 3.4x³-8.3x²+12.2x¹-48x

Step-by-step explanation:

using power rule we have to find the derevative of a function

f(x) = 3x⁴-8x³+12x²-48x+25

f(x) = 3x⁴-8x³+12x²-48x+25

f¹(x) = 3.4x³-8.3x²+12.2x¹-48

f¹(x) = 12x³-24x²+24x¹-48

f¹(x)= 12(x³-2x²+2x-4)

JAI SHREE KRISHNA