Question

find the derivative of the following. pllz help me

Answer 1

Hi...☺

Here is your answer...✌
=================================

$y = \cos( logx )^{2} \\ \\ Using \: chain \: rule ,\\ \\ \frac{dy}{dx} = - \sin( logx )^{2} \times 2 logx \times \frac{1}{x} \\ \\ = \frac{ - 2 \sin( logx ) {}^{2} . logx }{x}$

Answer 2

The given is
y = cos(logx)^2

so

dy/dx = d[cos(logx)^2

= -sin(logx)^2 × d[(logx)^2

= -sin(logx)^2 × 2 × d(logx)

= -sin(logx)^2 × 2(logx) × 1/x
[f'(x)^n = n[f(x)^n-1]

= [-2(logx)sin(logx)^2]/x

this is ur answer
♡♥♡♥♡♥♡♥♡♥♡♥