Find the derivative of the given functions from first principle:
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first principle se solve karna hai
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Answer:
-2/x³
Step-by-step explanation:
f(x) = 1/x²
f'(x) = Lim h- 0 (f(x + h) - f(x) )/ h
=> f'(x) = Lim h- 0 (1/(x + h)² - 1/x² )/ h
=> f'(x) = Lim h- 0 (x² - (x + h)² )/ (h((x + h)²x²)
=> f'(x) = Lim h- 0 (-h² - 2hx )/ (h((x + h)²x²)
=> f'(x) = Lim h- 0 (-h - 2x )/ ((x + h)²x²)
putting h = 0
=> f'(x) = -2x/ (( x²)(x²) )
=> f'(x) = -2/x³
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