Physics, asked by HiteshParmar240, 1 year ago

find the derivative of x^-2 + x^2 with respect to x​

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Answers

Answered by Anonymous
12

Question

Find the derivative of the following w.r.t to x

 \large{ \sf{ {x}^{ - 2} +  {x}^{2}  }}

Solution

Given Expression,

 \large{ \sf{y =  {x}^{ - 2} +  {x}^{2}  }}

To find

Derivative of the above equation w.r.t to x

Power Rule

 \large{ \tt{ {x}^{n} } = n {x}^{n - 1} }

Now,

  \sf{y' =  \frac{d( {x}^{ - 2} +  {x}^{2} ) }{dx} } \\  \\  \implies \: \sf{y' =  \frac{d( {x}^{ - 2} )}{dx} +  \frac{d(x {}^{2} )}{dx}  } \\  \\  \large{\implies \:   \boxed{ \boxed{\sf{y' = 2x - 2 {x}^{ - 3} }}}}

Answered by αmαn4чσu
25

Solution

 \sf{y' = \frac{d( {x}^{ - 2} + {x}^{2} ) }{dx} } \\ \\ \implies \: \sf{y' = \frac{d( {x}^{ - 2} )}{dx} + \frac{d(x {}^{2} )}{dx} } \\ \\ \large{\implies \: \boxed{ \boxed{\sf{y' = 2x - 2 {x}^{ - 3} }}}}

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