find the derivative of x^-3(5+3x)
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Answered by
7
5+3x/x^3
Using quotient rule,
=x^3d(5+3x)/dx-(5+3x)d(x^3)/(x^3)^2
=x^3(3)-(5+3x)(3x^2)/x^6
=3x^3-15x^2-9x^3/x^6
=-6x^3-15x^2/x^6
=-6/x^3-15/x^4
Using quotient rule,
=x^3d(5+3x)/dx-(5+3x)d(x^3)/(x^3)^2
=x^3(3)-(5+3x)(3x^2)/x^6
=3x^3-15x^2-9x^3/x^6
=-6x^3-15x^2/x^6
=-6/x^3-15/x^4
anisha70:
x^-3 is in multiply . How it become in divide
Answered by
20
x^-3(5+3x)
(5+3x)(x^-3)'+(x^-3)(5+3x)'
(5+3x)(-3x^-4)+3x^-3)
-15-9x/x^4 +3/x^3
-15-9x+3x/x^4
-3/x^4(5+3x-x)
-3/x^4(5+2x)
(5+3x)(x^-3)'+(x^-3)(5+3x)'
(5+3x)(-3x^-4)+3x^-3)
-15-9x/x^4 +3/x^3
-15-9x+3x/x^4
-3/x^4(5+3x-x)
-3/x^4(5+2x)
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