Question

find the derivative of (x+sinx)/tanx​

Answer 1

Step-by-step explanation:

Next, take the natural logarithm of both sides and use a property of logarithms to get ln(y)=tan(x)ln(sin(x)) . =1+ln(sin(x))sec2(x) . Multiplying both sides by y=sin(x)tan(x) now gives the final answer to be ddx(sin(x)tan(x))=(1+ln(sin(x))sec2(x))⋅sin(x)tan(x) .