Math, asked by khushirana1723, 11 months ago

find the derivative of x²+1/x²​

Answers

Answered by ihrishi
2

Step-by-step explanation:

Let  \: \: y =  {x}^{2}  +  \frac{1}{ {x}^{2} }  \\  differentiating \: w.r.t. \: x \: both \:   sides :  \\  \\  \frac{dy}{dx}  =  \frac{d}{dx} ({x}^{2}  +  \frac{1}{ {x}^{2} }) \\  \\  = \frac{d}{dx} {x}^{2}  +  \frac{d}{dx}  {x}^{ - 2} \\  \\  = 2x \times \frac{d}{dx} \: x + ( - 2) \times {x}^{ - 2 - 1}  \times   \frac{d}{dx} {x} \\  \\ =  2x \times 1 - 2 {x}^{ - 3}\times 1  \\  \\   = 2x  - 2 {x}^{ - 3} \\  \\  = 2x -  \frac{2}{ {x}^{ 3} }  \\  \\  =  \frac{2( {x}^{4}  - 1)}{ {x}^{3} } \\  \\  =  \frac{2( {x}^{2}   +  1)( {x}^{2} - 1)}{ {x}^{3} }  \\  \\ =  \frac{2( {x}^{2}   +  1)( {x}  + 1)( {x} - 1)}{ {x}^{3} }  \\  \\ thus \\  \\  \purple { \boxed{\frac{dy}{dx}  ({x}^{2}  +  \frac{1}{ {x}^{2} })    = \frac{2( {x}^{2}   +  1)( {x}  + 1)( {x} - 1)}{ {x}^{3} }}}

Answered by Sam5093
0

Answer:

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