Question

find the derivative of (x²+2) (x³-3x²+4) (x⁴-1)
full explanation please​

Answer 1

Answer:

here that so simple question

Step-by-step explanation:

$\frac {d}{dx} (x^2+2)(x^3-3x+4)(x^4-1)$ = $(2x + 0)(3x^2 -3 +4)(4x^3 - 0)$

$=(2x)(3x^2-3)(4x^3)$

i hope it helpful