Math, asked by ahsantariq991, 5 months ago

Suppose a jar contains 15 red marbles, 20 blue marbles, 5 green marbles, and 16 yellow marbles. If you randomly select one marble from the jar, what is the probability that you will have a red or green marble? *




Answers

Answered by akanshagarwal2005
2

Answer:

The total number of marbles is 5 + 32 = 37. You select a marble 2 times.

The 1st time you pick a marble, the probability of selecting red is 5/37.

Since there is no replacement, now we only have 4 red marbles to choose from a total of 36 marbles. So the second time the probability is 4/36.

Now we multiply the 2 answers:

(5/37) * (4/36) = 0.015015, or rounded to 3 decimal places, 0.015.

Answered by XxxRAJxxX
4

Answer:

5/19

Step-by-step explanation:

P(E) = \bf \it \frac{Possible \: Outcomes}{Total \: Outcomes}

Possible Outcomes = Red Marbles amd Green Marbles

  • Red Marbles = 15
  • Green Marbles = 5

=> 5 + 15 => 20 marbles

Total Outcomes = Number of total marbles

=> 15 + 20 + 5 + 16

=> 56 marbles

Therefore,

→ P (Having red or a green marble) = 20/56

=> 5/19

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