Question

Find the derivative of xsinx using first principle?

Answer 1

Hope this helps you.

Answer 2

$\mathbb{ \ \ A\ N\ S\ W\ E\ R\: \: }$

• if y=f(x) g (x)

then differentiation w.r.t.x

• dy/dx=f(x) dg(x)/dx+g(x)df(x)/dx

Now Use This

• y=x.sinx
• dy/dx=x.d (sinx)/dx+sinx.dx/dx
• =x.cosx+sinx