Find the derivative of y = (3x+5)^7.
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according to the equation,
(a + b)^2=a^2 +b^2+2ab
here a= 3x
b=5
(3x^2) +5^2 + 2(3x)(5)
9x^2 +25+30x
9x^2 +15x +15x +25
3x(3x+5)+5(3x+5)
(3x+5)(3x+5)=0
3x+5=0
3x= -5
x=-5/3
(a + b)^2=a^2 +b^2+2ab
here a= 3x
b=5
(3x^2) +5^2 + 2(3x)(5)
9x^2 +25+30x
9x^2 +15x +15x +25
3x(3x+5)+5(3x+5)
(3x+5)(3x+5)=0
3x+5=0
3x= -5
x=-5/3
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