Question

Find the derivative of. y= log e sin x​

Answer 1

Given that y=log(sinx), we need to find the value of

dx

dy

We know that the derivative of log(x) w.r.t x is

x

1

⟹

dx

dy

=

dx

d

(log(sinx))=

sinx

1

×

dx

d

(sinx)=

sinx

1

×cosx=cotx

Hence,

dx

dy

=cotx

Answer 2

Answer:

cot x

Explanation:

Y=log e Sin x

dy/dX= 1/sinx * cos x. (chain rule)

=cos x/sinx

= cot x