Question

find the derivative of y= sec(tan x)

Answer 1

If, y=sec(f(x))

then using chain rule, y'=sec(f(x))tan(f(x))f'(x)

In same way,

y'=sec(tan(x))tan(tan(x))(tan(x))'

y'=sec(tan(x))tan(tan(x))(sec2(x))

Answer 2

Answer:

derivative of :

tan x = sec^2 x

sec x = sec x tan x

hope you've understood

just leave it at sec x, it's for √x which I've solved

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