find the derivative using first principle of x3-27
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Answer:
= 0 + 3x2 = 3x2
Step-by-step explanation:
First we write the formula
f'x lin x→0 = f(x+h) - f(x) / h
now f'x = x3 -27
=limh→0[(x+h)3−27]−(x3−27)h=
limh→0[(x+h)3−27]−(x3−27)h
=limh→0x3+h3+3x2h+3xh2−x3h
=limh→0x3+h3+3x2h+3xh2−x3h
=limh→0h3+3x2h+3xh2h
=limh→0h3+3x2h+3xh2h
=limh→0(h2+3x2+3xh)
=limh→0(h2+3x2+3xh)
=0+3x2+0=3x2=0+3x2+0=3x2
= 0 + 3x2 = 3x2
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