Math, asked by sujal4855, 1 year ago

rationalize the denominator of 4root3+5root2upon4root3+3root2

Answers

Answered by abhinashtv
0

4 \sqrt{3 }  + 5 \sqrt{2}   \div 4 \sqrt{3 }   + 3 \sqrt{2}  \times 4 \sqrt{3}  - 3 \sqrt{2}  \div 4 \sqrt{3}  - 3 \sqrt{2}  = 3 + 4 \sqrt{6}  \div 5
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