Question

find the derivatives of the following functions (x^2 -1)/x​

Answer 1

Answer:

(x²+1)/x²

Step-by-step explanation:

d/dx [(x² -1)/x] = d/dx [x-(1/x)]  

                      = d/dx (x) - d/dx(1/x)

                      =   1 - d/dx (x^-1)  

                      =   1 - (-1)(x^-2)              ∵d/dx(x^n) = n{x^(n-1)}

                      =   1 + (x^-2)

                      =   1 + 1/x² = (x²+1)/x²