Question

Find the derivatives of the function f(x) = (x – 1) (x – 2) from first principles.

Answer 1

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$\longrightarrow \sf f(x) = (x - 1)(x - 2) \\ \\\longrightarrow \sf f(x) = {x}^{2} - 2x - x + 2 \\ \\\longrightarrow \sf f(x) = {x}^{2} - 3x + 2 \\ \\ \longrightarrow \boxed{\sf f'(x) = 2x - 3}$

Answer 2

$\huge \bf \red{S} \pink{O} \orange{L} \green{U} \purple{T} \orange{I} \pink{O} {N}{ \green{...}}$

$⟶f(x)=(x−1)(x−2) \\ ⟶f(x)=x2−2x−x+2 \\ ⟶f(x)=x2−3x+2 \\ ⟶f′(x)=2x−3$