find the derivatives of the sin(cos x) with respect to x
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It will be cos(cos x)*-Sinx
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Answer:
-cos(cosx)*sinx
Step-by-step explanation:
dy/dx of sinx(cosx) = derivative of outer function w.r.t to inner function multiplied by the derivative of inner function as per chain rule
= cos(cosx)*d(cosx)/dx
= -cos(cosx)*sinx
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