Find the derivatives w.r.t.x from first principle:
cos (2x+3)
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The way to do this is by using the chain rule.
The derivative of cos(x) is −sin(x):
ddxcos(2x+3)=−sin(2x+3)⋅ddx(2x+3)
The derivative of 2x+3 is 2, so the full derivative becomes:
ddxcos(2x+3)=−2⋅sin(2x+3)
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The derivative of cos(x) is −sin(x):
ddxcos(2x+3)=−sin(2x+3)⋅ddx(2x+3)
The derivative of 2x+3 is 2, so the full derivative becomes:
ddxcos(2x+3)=−2⋅sin(2x+3)
HOPE IT HELPS YOU
PLEASE MARK ME AS BRAINLIEST.........
-----------------------------
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