Question

Find the derivatives w.r.t.x from first principle:
log(x+7)

Answer 1

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Answer 2

Answer:

$\frac{1}{x+7}$

Step-by-step explanation:

Here, the given equation is

log(x+7)

and we find the derivatives of log(x+7) with respect to x in the form of first principle

we know that the first derivative of log x with respect to x is $\frac{1}{x}$

so, differentiating log(x+7) with respect to x, we get the first derivative

$\frac{d}{dx} log (x+7)$

= $\frac{1}{x+7}$

So, the answer will be

$\frac{1}{x+7}$