Question

Find the derivatives w.r.t.x:
$\rm e^{x} + a^{x} - \log x$

Answer 1

here is ur Answer ✍️✍️

Answer 2

To find the derivative of the given function with respect to x,we know that

$\frac{d(e^{x})}{dx}=e^{x}\\\\\frac{d(a^{x})}{dx}={a}^{x} log(a)\\\\\frac{d(log \: x)}{dx}=\frac{1}{x}$

$\frac{d}{dx} (\rm e^{x} + a^{x} - \log x) \\ \\ = \frac{d(e^{x})}{dx} \: + \frac{d(a^{x})}{dx} - \frac{d(log \: x)}{dx} \\ \\ = {e}^{x} + {a}^{x} log(a) - \frac{1}{x}$
these are the direct formula's of differentiation,thus apply directly.

Hope it helps you.