Question

find the derivatives
y=2/3x^1/3​

Answer 1

Answer:

$y = \frac{2}{ {3x}^{ \frac{1}{3} } } \\ \frac{dy}{dx} = \frac{2d {x}^{ - \frac{1}{3} } }{3dx} \\ \: \: \: \: \: \: \: = \frac{2 {x}^{ \frac{ - 4}{3} } }{3}$

hope this will help u....