find the diagonal of a rectangle whose length is 16 cm and area is 192 sq .CM.
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area =length *breadth
192= 16 * breadth
breadth= 192/16
=12
diagonal = under root 16 sq + 12 sq
diagonal =20cm
192= 16 * breadth
breadth= 192/16
=12
diagonal = under root 16 sq + 12 sq
diagonal =20cm
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hey friends
Area = 196
Length = 16
Breadth = Let's assume X
Area = length × breadth
196 = 16 × X
X = 196 ÷ 16
X = 12
Diagonal = √16sq + 12sq = 30cm
Diagonal is 30 cm.
Hope it is helpful...
Please mark as brainliest..
Thank you
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Area = 196
Length = 16
Breadth = Let's assume X
Area = length × breadth
196 = 16 × X
X = 196 ÷ 16
X = 12
Diagonal = √16sq + 12sq = 30cm
Diagonal is 30 cm.
Hope it is helpful...
Please mark as brainliest..
Thank you
:-)
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