Find the diagonal of the rectangle whose sides are in the ratio 4:3 .the area of the rectangle is 48 m
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Answer:
let length= 4x
. breadth=3x
Area=48
4x*3x=48
12x^2=48
x^2=48/12
x=2
Now length=4*2=8m
. breadth=3*2=6m
(diagonal)^2=(8)^2+(6)^2
diagonal =10m
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