find the diagonals of a rectangle whose length is 35cm and breadth is 12cm
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let the rectqngle be ABCD
ang.A is 90
therefore ADB right angled triangle
BD is hypotenuse
BD^2=AD^2+AB^2/pythagoras theorrm/
BD^2=12^2+35^2
BD^2=144+1225
BD^2= 1369cm
BD=37cm
BD is diagonal
therefore length of both diagonals is 37 cm because diagonals is equal in rectangle
ang.A is 90
therefore ADB right angled triangle
BD is hypotenuse
BD^2=AD^2+AB^2/pythagoras theorrm/
BD^2=12^2+35^2
BD^2=144+1225
BD^2= 1369cm
BD=37cm
BD is diagonal
therefore length of both diagonals is 37 cm because diagonals is equal in rectangle
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Answer:
Diagonal = 37 cm
Step-by-step explanation:
Given that ;
Length = 35 cm
Breadth = 12 cm
We know that ;
Diagonal of rectangle =
⇒ Diagonal =
⇒ Diagonal =
⇒ Diagonal =
⇒ Diagonal = ± 37
Taking the positive value, the diagonal of the rectangle is 37 cm.
_______________________
Extra information :
Area of rectangle = length * Breadth
Length of rectangle = Area / Breadth
Breadth of rectangle = Area / length
Diagonal = √l² + ω²
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