Question

find the diagonals of a rectangle whose length is 35cm and breadth is 12cm​

Answer 1

let the rectqngle be ABCD

ang.A is 90

therefore ADB right angled triangle

BD is hypotenuse

BD^2=AD^2+AB^2/pythagoras theorrm/

BD^2=12^2+35^2

BD^2=144+1225

BD^2= 1369cm

BD=37cm

BD is diagonal

therefore length of both diagonals is 37 cm because diagonals is equal in rectangle

Answer 2

Answer:

Diagonal = 37 cm

Step-by-step explanation:

Given that ;

Length = 35 cm

Breadth = 12 cm

We know that ;

Diagonal of rectangle = $\sqrt{l^2 + b^2}$

⇒ Diagonal = $\sqrt{(35)^2 + (12)^2}$

⇒ Diagonal = $\sqrt{1225 + 144}$

⇒ Diagonal = $\sqrt{1369}$

⇒ Diagonal = ± 37

Taking the positive value, the diagonal of the rectangle is 37 cm.

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Extra information :

Area of rectangle = length * Breadth

Length of rectangle = Area / Breadth

Breadth of rectangle = Area / length

Diagonal = √l² + ω²