Question

find the diameter of quadratic equation xsquar -4x -1 =0

Answer 1

${x}^{2} - 4x - 1 = 0 \\ d = \sqrt{ {b}^{2} - 4ac} \\ d = \sqrt{ { (- 4)}^{2} - 4(1)( - 1) } \\ = \sqrt{16 + 4} = \sqrt[]{20}$
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